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Three distinct points are plotted at random on a Cartesian plane, for which -1000 ≤ x, y ≤ 1000, such that a triangle is formed.
Consider the following two triangles:
A(-340,495), B(-153,-910), C(835,-947)
X(-175,41), Y(-421,-714), Z(574,-645)
It can be verified that triangle ABC contains the origin, whereas triangle XYZ does not.
Using triangles.txt (right click and 'Save Link/Target As...'), a 27K text file containing the co-ordinates of one thousand "random" triangles, find the number of triangles for which the interior contains the origin.
NOTE: The first two examples in the file represent the triangles in the example given above.
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I`ve exploited the idea that for origin to be in the triangle interior, triangle lines segments should cross x and y axis 2 times: x+ / x- and y+ / y-.
Basically it is enough to check does triangle cross y+ and y- axis parts, but I didn`t know that and checked both axis. This worked too :-)
Solution ( C# as always):
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;
namespace ConsoleApplication1
{
class Program
{
static int[][] ReadTriangleCoordinates(string file)
{
int[][] res;
StreamReader sr = new StreamReader(file);
res = Array.ConvertAll(sr.ReadToEnd().TrimEnd().Split("\n".ToCharArray()),
s => {return Array.ConvertAll(s.Split(",".ToCharArray()),
n => { return int.Parse(n); }) ;});
sr.Close();
return res;
}
static void CrossesAxisAt(int x1,
int y1,
int x2,
int y2,
out double? xAt,
out double? yAt)
{
int dx = x2 - x1;
int dy = y2 - y1;
int xmin = Math.Min(x1, x2);
int ymin = Math.Min(y1, y2);
int xmax = Math.Max(x1, x2);
int ymax = Math.Max(y1, y2);
double? xcross;
double? ycross;
double a;
double b;
if (dx == 0)
{
xcross = x1;
ycross = null;
}
else if (dy == 0)
{
xcross = null;
ycross = y1;
}
else
{
a = (double)dy / (double)dx;
b = y1 - (a * x1);
xcross = -(b / a);
ycross = b;
}
if (xcross != null)
{
if (xcross < xmin || xcross > xmax
|| ymin > 0 || ymax < 0)
xcross = null;
}
if (ycross != null)
{
if (ycross < ymin || ycross > ymax
|| xmin > 0 || xmax < 0)
ycross = null;
}
xAt = xcross;
yAt = ycross;
}
static bool ContainsOrigin(int[] abc)
{
double? xc1, xc2, xc3;
double? yc1, yc2, yc3;
int xposc = 0, xnegc = 0, yposc = 0, ynegc = 0;
bool res;
CrossesAxisAt(abc[0], abc[1], abc[4], abc[5], out xc1, out yc1);
CrossesAxisAt(abc[0], abc[1], abc[2], abc[3], out xc2, out yc2);
CrossesAxisAt(abc[2], abc[3], abc[4], abc[5], out xc3, out yc3);
xposc = ((xc1 > 0) ? 1 : 0) + ((xc2 > 0) ? 1 : 0) + ((xc3 > 0) ? 1 : 0);
xnegc = ((xc1 < 0) ? 1 : 0) + ((xc2 < 0) ? 1 : 0) + ((xc3 < 0) ? 1 : 0);
yposc = ((yc1 > 0) ? 1 : 0) + ((yc2 > 0) ? 1 : 0) + ((yc3 > 0) ? 1 : 0);
ynegc = ((yc1 < 0) ? 1 : 0) + ((yc2 < 0) ? 1 : 0) + ((yc3 < 0) ? 1 : 0);
if (xposc > 0 && xnegc > 0 && yposc > 0 && ynegc > 0)
res = true;
else
res = false;
return res;
}
static int TrianglesWithOrigin(string file)
{
int[][] tr = ReadTriangleCoordinates(file);
int trcount = 0;
for (int i = 0; i < tr.Length; i++)
{
if (ContainsOrigin(tr[i]))
trcount++;
}
return trcount;
}
static void Main(string[] args)
{
Console.WriteLine(TrianglesWithOrigin("C:\\ProjectEuler\\triangles.txt"));
Console.ReadLine();
}
}
}
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